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33x^2=0.21-2x
We move all terms to the left:
33x^2-(0.21-2x)=0
We add all the numbers together, and all the variables
33x^2-(-2x+0.21)=0
We get rid of parentheses
33x^2+2x-0.21=0
a = 33; b = 2; c = -0.21;
Δ = b2-4ac
Δ = 22-4·33·(-0.21)
Δ = 31.72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{31.72}}{2*33}=\frac{-2-\sqrt{31.72}}{66} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{31.72}}{2*33}=\frac{-2+\sqrt{31.72}}{66} $
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